(2y^2-128)/(y^2)=0

Solution for (2y^2-128)/(y^2)=0 equation:

(2y^2-128)/(y^2)=0


Domain of the equation: y^2!=0

y^2!=0/

y^2!=√0

y!=0

y∈R


We multiply all the terms by the denominator


(2y^2-128)=0

We get rid of parentheses

2y^2-128=0

a = 2; b = 0; c = -128;
Δ = b2-4ac
Δ = 02-4·2·(-128)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*2}=\frac{-32}{4}
=-8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*2}=\frac{32}{4}
=8
$